Problems on Division of Decimal Fractions 

Here in this topic deals with division of decimals fractions in the form of story sums. A story will be given along with the sum and we need to determine what operation we need to perform to solve the problem along with writing proper statements.

Here are few examples on problems on division of decimals to illustrate the topic:


1. If the cost of 5 notebooks is $85.85. Find the cost of 1 notebook.

Solution:

Cost of 5 notebooks = $85.85

Cost of 1 notebook =  $85.85 ÷ 5

Problems on Division of Decimal Fractions

Therefore, the cost of one note book is $17.17

Here the cost of 5 notebooks is given and we need to find the cost of 1 notebook. Hence we need to divide the cost of 5 note books by 5 to get the cost of 1 notebook.


2. There are few bags of rice weighing 7.3 kg each. Now on weighing all the bags it is found that the total weight of all the bags is 65.7 kg. Find the number of bags of rice.

Solution:

Total weight of all the bags of rice = 65.7 kg

Weight of each bag of rice            =   7.3 kg

Therefore, no. of bags of rice        = 65.7 ÷ 7.3 kg

(Here there is equal no. of decimal points in both the divisor and the dividend so we will divide both the numbers by 10 as there is 1 place after the decimal point in the divisor

65.7/10 ÷ 7.3/10

As we have learnt in other subtopics while dividing a fraction by another fraction is that a fraction is multiplied by the reciprocal of another fraction likewise we will do so

= 657/10 × 10/73

= (657 × 10) / (10 × 73)

On changing it into lowest terms we get,

= 657/73

Now in the normal way of division we will divide both the numbers)

= 657 ÷ 73

Problems on Division of Decimal Fractions

Therefore, there are 9 bags of rice weighing 7.3 kg each.

Here in this sum the total weight of few bags of rice is given and weight of 1 bag of rice is also given so we need to divide the total weight of all the bags by the weight of one bag to get the total no. of bags of rice.


3. If the product of two numbers is 153.9. If one number is 10. Find the other number.

Solution:

The product of two numbers = 153.9

One number = 10

Therefore other no. is 153.9 ÷ 10

                             = 15.39

The other number is 15.39

Here we are not doing actual division as it is a division by 10 that means 1 zero hence the decimal point in the dividend will move by one place to the left to get the answer.


4. 25.5 m long rope is cut into five pieces. Find the length of each piece.

Solution:

Length of rope = 25.5 m

No. of pieces = 5

Length of each piece = 25.5 ÷ 5

Problems on Division of Decimal Fractions

Therefore, the length of each piece = 5.1 m

Here the total length of rope is given 25.5 m and it is cut into 5 pieces. Hence in order to find the length of each piece we have to divide 25.5 by 5.

You might like these



5th Grade Math

From Problems on Division of Decimal Fractions to HOME PAGE

New! Comments

Have your say about what you just read! Leave me a comment in the box below.


Recent Articles

  1. Amphibolic Pathway | Definition | Examples | Pentose Phosphate Pathway

    Jun 06, 24 10:40 AM

    Amphibolic Pathway
    Definition of amphibolic pathway- Amphibolic pathway is a biochemical pathway where anabolism and catabolism are both combined together. Examples of amphibolic pathway- there are different biochemical…

    Read More

  2. Respiratory Balance Sheet | TCA Cycle | ATP Consumption Process

    Feb 18, 24 01:56 PM

    ATP Synthase in Mitochondria
    The major component that produced during the photosynthesis is Glucose which is further metabolised by the different metabolic pathways like glycolysis, Krebs cycle, TCA cycle and produces energy whic…

    Read More

  3. Electron Transport System and Oxidative Phosphorylation | ETC |Diagram

    Feb 04, 24 01:57 PM

    Electron Transport Chains
    It is also called ETC. Electron transfer means the process where one electron relocates from one atom to the other atom. Definition of electron transport chain - The biological process where a chains…

    Read More

  4. Tricarboxylic Acid Cycle | Krebs Cycle | Steps | End Products |Diagram

    Jan 28, 24 12:39 PM

    Aerobic Respiration
    This is a type of process which execute in a cyclical form and final common pathway for oxidation of Carbohydrates fat protein through which acetyl coenzyme a or acetyl CoA is completely oxidised to c…

    Read More

  5. Aerobic Respiration | Definition of Aerobic Respiration | Glycolysis

    Dec 15, 23 08:42 AM

    Aerobic Respiration
    This is a type of respiration where molecular free oxygen is used as the final acceptor and it is observed in cell. Site of Aerobic Respiration - Aerobic respiration is observed in most of the eukaryo…

    Read More